Question

find the least number which when divided by 2 3 4 5 and 6 leaves remainders 1 2 3 4 and 5 respectively​

Answer 1

Answer:

59

Step-by-step explanation:

By the Rule of LCM, the smallest number which when divided by a,b,c... to leave remainders p, q, r..., such that a - p = b - q = c - r = k, then the number = LCM (a,b,c) - k

here k = 2 - 1 = 3 - 2 = 4 - 3 = 5 - 4 = 6 - 5 = 1

LCM(2,3,4,5,6) = 60

Therefore the number is 60 - 1 = 59