Question

Find the least number which when divided by 2, 3, 4 and 5 leaves a remainder 3. but when divided by 9 leaves no remainder?

Answer 1

Answer:

Take LCM then add 3 answer is 63

Answer 2

Given,

Number when divided by 2,3,4 and 5 leaves 3 as the remainder.

The number is completely divisible by 9

To Find,

The number  =?

Solution,

Let the number be x

LCM of (2,3,4,5) = 2 * 3 * 2 * 5

LCM of (2,3,4,5) = 60

x = 60

But n leaves remainder 3 when divided by 2,3,4 and 5

x = 60 + 3

x = 63

For checking, the number is completely divisible by 9 which is

63 / 9 = 7

Hence,  the least number when divided by 2, 3, 4, and 5 leaves a remainder of 3. but when divided by 9 leaves no remainder is 63.