Question

Find the least number which when divided
by 2, 3, 4 and 5 will leave remainders 1, 2,
3 and 4 respectively.​

Answer 1

${\huge{\colorbox{crimson}{☆ANSWER☆:-}}}$

Here 4 – 1 = 3, 5 – 2 = 3, 6 – 3 = 3

∴ The required Number

= LCM of (4, 5, 6) – 3

= 60 – 3

= 57.

Answer 2

Answer:

This number is 1

Because you have to know this concept