Find the least number which when divided by 20 25 35 and 40 leaves remainder 14 19 29 and 34 respectively
Answers
Answered by
1
Heya !!!
20 - 14 = 6
25 - 19 = 6
35 - 29 = 6
40 - 34 = 6
Prime factorisation of 6 = 2 × 3
LCM of 20 , 25 , 35 , 40 = 6
Hence,
Required Number = 6
HOPE IT WILL HELP YOU...... :-)
20 - 14 = 6
25 - 19 = 6
35 - 29 = 6
40 - 34 = 6
Prime factorisation of 6 = 2 × 3
LCM of 20 , 25 , 35 , 40 = 6
Hence,
Required Number = 6
HOPE IT WILL HELP YOU...... :-)
Answered by
1
hi
aim : Find the least number which when divided by 20 25 35 and 40 leaves remainder 14 19 29 and 34 respectively
20 - 14 = 6
25 - 19 = 6
35 - 29 = 6
40 - 34= 6
now let us find the hcf of 6,6,6,6,
6 = 2*3
6 = 2*3
6 = 2*3
6 = 2*3
so hcf of 6,6,6,6 = 2*3 = 6
hence 6 is the least number which when divided by 20 25 35 and 40 leaves remainder 14 19 29 and 34 respectively
hope it helps u
:)
aim : Find the least number which when divided by 20 25 35 and 40 leaves remainder 14 19 29 and 34 respectively
20 - 14 = 6
25 - 19 = 6
35 - 29 = 6
40 - 34= 6
now let us find the hcf of 6,6,6,6,
6 = 2*3
6 = 2*3
6 = 2*3
6 = 2*3
so hcf of 6,6,6,6 = 2*3 = 6
hence 6 is the least number which when divided by 20 25 35 and 40 leaves remainder 14 19 29 and 34 respectively
hope it helps u
:)
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