Math, asked by phulbahadurshahi, 8 months ago

Find the least number which when divided by 20 30 and 40 leaves 3 AS remainder in each case​

Answers

Answered by skumarunnao4
0

Answer:

123

Step-by-step explanation:

Since LCM of 20,30 and 40 is 120 and remainder is 3

therefore the required number will be 120+3 = 123

Answered by R3ADJ
0

Answer:

first,

LCM of 20, 30 and 40

=120

now, add remainder

= 120+3

=123

therefore, 123 when divided by 20, 30 and 40 leaves remainder as 3

Step-by-step explanation:

When there are Q's with remainder:

  • If it's written *divisible by* so it will be LCM and we have to first find the LCM and then add remainder
  • If the is *divides* so it will be HCF and we have to first subtract remainders and then find HCF

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