Find the least number which when divided by 20 30 and 40 leaves 3 AS remainder in each case
Answers
Answered by
0
Answer:
123
Step-by-step explanation:
Since LCM of 20,30 and 40 is 120 and remainder is 3
therefore the required number will be 120+3 = 123
Answered by
0
Answer:
first,
LCM of 20, 30 and 40
=120
now, add remainder
= 120+3
=123
therefore, 123 when divided by 20, 30 and 40 leaves remainder as 3
Step-by-step explanation:
When there are Q's with remainder:
- If it's written *divisible by* so it will be LCM and we have to first find the LCM and then add remainder
- If the is *divides* so it will be HCF and we have to first subtract remainders and then find HCF
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