Find the least number which when divided by 21,28,36 and 45 leaves a remainder 9 in each case.
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Answer : 9
As the question is to find the least number, it is obviously the remainder itself.
Every number when divided by higher number leaves the number as remainder and the quotient being '0'
As the question is to find the least number, it is obviously the remainder itself.
Every number when divided by higher number leaves the number as remainder and the quotient being '0'
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Here is ur answer friend!
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