Question

Find the least number which when divided by 22 and 26 leaves 6 as the remainder in each case.​

Answer 1

answer is 4

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Answer 2

Step-by-step explanation:

Find the least number which when divided by 12, leaves a remainder of 7, when divided by 15, leaves a remainder of 10 and when divided by 16, leaves a remainder of 11

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Answer

Correct option is

B

235

12=2

2

×3

15=3×5

16=2

4

LCM=2

4

×3×5=240

Now, the number has a remainder of 7 when divided by 12. Similarly, number has remainder 10 on dividing by 15 and remainder is 11 when divided by 16. In each case, we are 5 short of getting a zero remainder. So the desired number must be 240−5=235

Option B

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