Find the least number which when divided by 24,30 and 48 leaves 7 as remainder.
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Step-by-step explanation:
SOLUTION : To find the smallest number, we first find LCM ( least common multiple) of 24,30,48 & 60 and then add remainder 2 in the LCM. Hence, the smallest number which when divided by 24 ,30 ,48 and 60 leaves a remainder 2 in each case is 242.
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