Math, asked by skoolboy5612, 3 months ago

Find the least number which when divided by 24,30 and 48 leaves 7 as remainder.

Answers

Answered by EhsaaNada

Step-by-step explanation:

SOLUTION : To find the smallest number, we first find LCM ( least common multiple) of 24,30,48 & 60 and then add remainder 2 in the LCM. Hence, the smallest number which when divided by 24 ,30 ,48 and 60 leaves a remainder 2 in each case is 242.

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