Find the least number which when divided by 24, 36 and 54 leave remainder 5 in each case.
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Answer:
221
Step-by-step explanation:
What is the smallest number which when divided by 24, 36 and 54 gives a remainder of 5 each time? Therefore, the smallest number which when divided by 24, 26 and 54 gives a remainder of 5 each time is 221.
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