Find the least number which when divided by 24, 36 and 60 will leave in each case the same remainder 7
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Answer:
the number is 367
Step-by-step explanation:
first find the LCM of 24,36,60.
24 = 8*3
36 = 4*9
60 = 4*3*5
So LCM is 8*9*5 = 360
Now 360 is the smallest number which is perfectly divisble by 24, 36, 60.
And hence if we add 7 to 360 we get a number which leaves remainder 7 and is the smallest to do so = 360 +7 = 367
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