Math, asked by vivekraj222, 1 year ago

Find the least number which when divided by 24,48 and 96 leaves a remainder 3 in each case.

Answers

Answered by Anonymous
10
24-3=21
48-3=45
96-3=93.
LCM of 21,45,93
21=3 x 7
45= 3 x 3 x 5.
93=3 x 31.
LCM of 21,45 and 93 is 3 x7 x3 x 5 x 31 = 9765.
Hence the least number which when divided by 24,48 and 96 is 9765.


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