Find the least number which when divided by 24 and 15, leave 5 as remainder
in each case. please tell me I have to do now
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Step-by-step explanation:
LCM of 24 ,30 , and 54 is the smallest number divisible by the three numbers. If you add 5 to the LCM, the new number will be the number to give a remainder of 5 when when divided by any of the three numbers.
To find the LCM ( lowest common multiple) of the numbers , express each number as product of factors.
24 = 2*2*2*3
30 = 2*3*5
54 = 2*3*3*3
LCM = 2*3*2*2*5*3*3 =1080
(Factors that are common to all the three numbers are taken only once)
So the required number is 1080+5=1085
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