Question

Find the least number which when divided by 25, 40 and 60 leaves 8 as the remainder in each case.

Answer 1

5 goes into all of them but there is not going to be a remainder. Sorry.

Answer 2

Answer:

The required number which when divided by 25, 40 and 60 leaves 8 as the remainder in each case is 608.

Step-by-step explanation:

To find : The least number which when divided by 25, 40 and 60 leaves 8 as the remainder in each case?

Solution :  

We find the LCM of 25, 40 and 60.

2 | 25  40  60

2 | 25  20  30

2 | 25  10   15

3 | 25   5    15

5 | 25   5    5

5 |   5   1     1

  |   1    1     1

$LCM(25,40,60)=2\times 2\times 2\times 3\times 5\times 5$

$LCM(9,13)=600$

In each case it leaves a remainder 8 so we add 8 in the LCM of the numbers.

i.e. 600+8=608.

Therefore, The required number which when divided by 25, 40 and 60 leaves 8 as the remainder in each case is 608.