Question

Find the least number which when divided by 25, 40 and 60 leaves a remainder 7 in each case.​
Tell only correct answer...

Answer 1

Answer:

LCM of 25,40,60 =600

Remainder =7

600+7=607 is the required no.

Answer 2

Step-by-step explanation:

the required no. = LCM(25,40,60)+7

25 = 5×5 = 5²

40 = 2×2×2×5 = 2³×5

60 = 2×2×3×5 = 2²×3×5

LCM = highest power of factors = 2³×3×5² = 600

So, the required no = 600+7 = 607