Question

find the least number which when divided by 25,40 and 60 leaves 9 as a remainder in each case.​

Answer 1

Given:-

•As we are given some numbers 25,40 and 60 which leaves 9 as a remainder in each case.

To Find:-

•Find the least number.

Solution:-

As we have given some numbers 25,40 and 60 which leaves 9 as a remainder so firstly,we will take LCM.

$\: \: \sf \: 25 = 5 \times 5 \\ \\ \: \: \sf \: 40 = 2 \times 2 \times 2 \times 5 \\ \\ \: \: \sf \: 60 = 2 \times 2 \times 3 \times 5$

Now take LCM = 2^3 × 3 × 5^2 = 600

Hence,LCM of 25,40 and 60 is 600.

Now find the required no.

Required No. = 600 + 9 = 609

Hence,required number is 609.

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