Question

find the least number which when divided by 25 40 and 60 leave the reminder 7 in each case
Find the least number which when divided by 25 40 and 60 the remainder 7 in each case ​

Answer 1

Answer:

Factors of

25 = 5x5

40 = 2x2x2x5

60 = 2x2x3x5

LCM = 2x2x2x3x5x5 = 600

Add 7 to 600 to get 607 as the answer.

Answer 2

lcm of 25,40,60:600.

So the number is 600+7=607.

therefore 607 is the smallest no. which when divided by 25,50 and 60 leaves a remainder of 7.07