Find the least number which when divided by 28, 36 and 45 leaves a remainder 3 in each case.
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Therefore, the LCM of 21, 28, 36, and 45 is 1260. Example 2: Find the smallest number which when divided by 21, 28, 36, and 45 leaves 3 as the remainder in each case. ⇒ The required number = 1260 + 3 = 1263.
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