Math, asked by 987654321123456789, 1 year ago

Find the least number which when divided by 28 ,56 and 168 leaves 3 AS remainder in each case

Answers

Answered by monty842311

6

Answer:

Step-by-step explanation:

taking LCM of all the numbers

28=2×2×7

56=2×2×2×7

168=2×2×2×3×7

LCM=2×2×2×3×7=168

now 168 is divisible by all three numbers

adding 3 gives

171, is the answer

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