Question

Find the least number which when divided by 28 ,56 and 168 leaves 3 AS remainder in each case​

Answer 1

Answer:

Step-by-step explanation:

taking LCM of all the numbers

28=2×2×7

56=2×2×2×7

168=2×2×2×3×7

LCM=2×2×2×3×7=168

now 168 is divisible by all three numbers

adding 3 gives

171, is the answer