Question

find the least number which when divided by 3,4,5,6,10 and 12 leaves a reminder of 2 in each case ​

Answer 1

Answer:

2

Step-by-step explanation:

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Answer 2

LCM of 3,4,5,6,10 and 12 = 120

Required number = 120x +2

Suppose, Required number = N

13/N = reminder = 0

we have to find the least number that should divide N and reminder = 0

If, x = 8

Then,

N = 120 * 8 + 2

N = 960 + 2

N = 962

Therefore,

N = Required number = 962