Find the least number which when divided by 3 4 5 6 10 and 12 leaves a remainder of 2 in each case
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Answered by
2
hello!
here is your answer
First find the LCM of 3, 4, 5, 6, 10, and 12. The number you seek is LCM + 2
Prime factorizations:
3 = 3
4 = 2 x 2
5 = 5
6 = 2 x 3
10 = 2 x 5
12 = 2 x 2 x 3
LCM = 2 x 2 x 3 x 5 = 60
LCM + 2 = 62. There is your answer.
I hope this helps you.
Answered by
1
Answer:
62 is the answer as first take LCM of these number and then add 2 to the lcm of these numbers
Step-by-step explanation:
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