Question

Find the least number which when divided by 33, 44, and 55 leaves remainders 31, 42 and 53

respectively.​

Answer 1

Answer:

The answer is 658

Step-by-step explanation:

Hence, \(658\) is the smallest number when divided by \(33,\;44\;\text{and}\;55\)leaves remainders \(\;31,\;42\;\text{and}\;53\), respectively.

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Answer 2

Answer:

658. . . . . . . . . . . . .. . pls mark as brainlist