Math, asked by archita2027, 3 months ago

find the least number which when divided by 35,56,91 leave the same remainder 7 in each case ​

Answers

Answered by llNidhill
8

Given:

  • Divided by 35,56,91 leave the same remainder 7

To find:

  • Smallest Number

Solution:

  • 35=5×7
  • 56=2×2×2×7
  • 91=13×7
  • HM= 2×2×2×5×7×13=3640
  • Remainder = 7 in each case
  • So smallest number =3640+7=3647
  • Hence , Answer is 3647
Answered by LittleButterfly
0

Hey....

The smallest number which when divided by 35, 56 and 91 = LCM(35,56,91)

LCM=2³×5×7×13=3640

The smallest number that when divided by 35, 56, 91 leaves a remainder 7 in each case = 3640 + 7 = 3647.

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