find the least number which when divided by 35,56,91 leave the same remainder 7 in each case
Answers
Answered by
8
Given:
- Divided by 35,56,91 leave the same remainder 7
To find:
- Smallest Number
Solution:
- 35=5×7
- 56=2×2×2×7
- 91=13×7
- HM= 2×2×2×5×7×13=3640
- Remainder = 7 in each case
- So smallest number =3640+7=3647
- Hence , Answer is 3647
Answered by
0
Hey....
The smallest number which when divided by 35, 56 and 91 = LCM(35,56,91)
LCM=2³×5×7×13=3640
The smallest number that when divided by 35, 56, 91 leaves a remainder 7 in each case = 3640 + 7 = 3647.
Similar questions