Question

find the least number which when divided by 35,56,91 leave the same remainder 7 in each case ​

Answer 1

Given:

• Divided by 35,56,91 leave the same remainder 7

To find:

• Smallest Number

Solution:

• 35=5×7
• 56=2×2×2×7
• 91=13×7
• HM= 2×2×2×5×7×13=3640
• Remainder = 7 in each case
• So smallest number =3640+7=3647
• Hence , Answer is 3647

Answer 2

Hey....

The smallest number which when divided by 35, 56 and 91 = LCM(35,56,91)

LCM=2³×5×7×13=3640

The smallest number that when divided by 35, 56, 91 leaves a remainder 7 in each case = 3640 + 7 = 3647.