Math, asked by rohini242005, 4 months ago

Find the least number which when divided by 35, 56 and 91 leaves the same remainder 7 in each case.

Answers

Answered by dushyant741

9

Step-by-step explanation:

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rohini242005: thanks for your answer

dushyant741: Mark it brainliest please

Answered by ashiswarup1

3

Answer:

LCM of 35, 56, 91 =

35 = 5 × 7

56 = 2 × 2 × 2 × 7

91 = 7 × 13

LCM = 3640

Therefore, the required number = 3640 + 7 = 3647

rohini242005: thank you

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