Find the least number which when divided by 35,56 and 91 leaves the remainder 7 in each case
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Answered by
10
Heya !!
Prime factorisation of 35 = 5 × 7
Prime factorisation of 56 = 2 × 2 × 2 × 7
Prime factorisation of 91 =7 × 13
LCM of 35 , 56 , 91 = 5 × 2 × 2 × 2 × 7 × 13 = 3633
Required number = LCM of 35,56 and 91 + 7 = 3633 + 7 = 3640.
Prime factorisation of 35 = 5 × 7
Prime factorisation of 56 = 2 × 2 × 2 × 7
Prime factorisation of 91 =7 × 13
LCM of 35 , 56 , 91 = 5 × 2 × 2 × 2 × 7 × 13 = 3633
Required number = LCM of 35,56 and 91 + 7 = 3633 + 7 = 3640.
Answered by
6
35 = 3 × 7
56 = 2 × 2 × 2 × 7
91 =7 × 13
LCM of 35,56,91 = 3633
Required number = LCM + 7 = 3633 + 7 = 3640.
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