Question

Find the least number which when divided by 35,56 and 91 leaves the remainder 7 in each case

Answer 1

Heya !!

Prime factorisation of 35 = 5 × 7

Prime factorisation of 56 = 2 × 2 × 2 × 7

Prime factorisation of 91 =7 × 13

LCM of 35 , 56 , 91 = 5 × 2 × 2 × 2 × 7 × 13 = 3633

Required number = LCM of 35,56 and 91 + 7 = 3633 + 7 = 3640.

Answer 2

35 = 3 × 7


56 = 2 × 2 × 2 × 7



91 =7 × 13

LCM of 35,56,91 = 3633

Required number = LCM + 7 = 3633 + 7 = 3640.