Math, asked by anaskhan16, 10 months ago

find the least number which when divided by 35, 56and 91 leave the same remainder 7 in each case​

Answers

Answered by vinaynagerkoti876
2

Step-by-step explanation:

find lcm of given no then add 7 in it

Answered by rajjbpathan
0

Answer:

Least number which can be divided by 35, 56 and 91 is 3640. Least number which when divided by 35, 56 and 91 leaves the same remainder 7 is3640 + 7 = 3647. Thus, the required number is3647.

Previous Question
Next Question
Similar questions
Math, 5 months ago
Convert 3 km, 6m into cm & millimeters?​
History, 5 months ago
What is the central idea of the passage?
English, 5 months ago
You are suffering from Chickenpox Write an application application to your Principal requesting him to grant you leave for two weeks.​
Physics, 10 months ago
GOVERNMENT OF TAMILNADU 12th standard new textbooks​...
Math, 10 months ago
The factors of 9x^2– 25y^2 are (a) (3x + 5y) (3x + 5y) (c) (3x + 5y) (3x - 5y) (b) (-3x + 5y) (3x - 5y) (d) none of these ​...
Physics, 1 year ago
How much force is required to stop a bus (10second) of mass 5000kg moving with a speed of 72km/h? please solve this problem in details.....
History, 1 year ago
who was the first Indian to foot on antartica...
Chemistry, 1 year ago
What is the forma for buta- 1, 3- diene...