Question

Find the least number which when divided by 36, 24 and 48 leaves remainder 33 21 and 45 respectively

Answer 1

Answer:

141

Step-by-step explanation:

using dividend=divisor*quotient+remainder

no can be written as

36a+33

24b+21

48c+45

these can also be written as

36a+36-3

24b+24-3

48c+48-3

to find the least no satisfying given condition find LCM of 36,24,48=144

so no is 144-3=141

Answer 2

Answer

Common difference of the divisor and the quotient = 3

LCM of 36, 24, 48 = 144

Dividend = 144 - 3

= 141