Find the least number which when divided by 4, 6 and 12 leaves 5 as remainder in each case.
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95
Step-by-step explanation:
To find the least number that when divided by 6, 15, and 18 leaves a remainder 5, we must first find the L.C.M. of 6, 15, and 18 and then add 5.
Find the L.C.M of 6, 15, and 18
6 = 2 × 3
15 = 3 × 5
18 = 2 × 3 × 3
L.C.M of 6, 15 and 18 = 2 x 3 x 3 x 5
L.C.M (6, 15 and 18) = 90
Therefore, the required number = 90+5 = 95
As a result, 95 is the smallest number, with a remainder of 5 in each case when divided by 6, 15, and 18.
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