Math, asked by harsh21ahlawat, 3 days ago

Find the least number which when divided by 40 48 and 56 leaves a remainder of 5 in each case

Answers

Answered by shubh17240

0

Answer:

hope it helps u

Step-by-step explanation:

1685

Explanation:

40 = 2 × 2 × 2 × 5

48 = 2 × 2 × 2 × 2 × 3

56 = 2 × 2 × 2 × 7

Hence, LCM of 40, 48 and 56 = 1680

Required number = 1680 + 5 = 1685

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