Math, asked by tripathir544, 7 months ago

find the least number
which when divided by 40,48and 56, leaves remainder 5in each case

Answers

Answered by monaaidasani051073

0

Answer:

2|40 2|48 2|56

2|20 2|24 2|28

2|10 2|12 2|14

5|5 2|6 7|7

=1 3|3 =1

=1

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