Find the least number which when divided by 40,50 & 60 leaves remainder 5 in case.
Answers
Answered by
1
Answer:
Subtract remainder from each number
40-5=35
50-5=45
60-5=55
Take LCM of new no.s is4165 .this is your answer.please mark as brainlest answer
Answered by
0
Step-by-step explanation:
first find lcm of these no.
40=2*2*2*5
50=2*5*5
60=2*2*3*5
lcm=600
the required no. which when divided leaves 5 remainder in each case will be
600+5
=605
Similar questions
Science,
4 months ago
Social Sciences,
4 months ago
Math,
4 months ago
Biology,
9 months ago
Political Science,
9 months ago
Chemistry,
1 year ago