Math, asked by AnkaniJogendra5979, 9 months ago

Find the least number which when divided by 40,50 & 60 leaves remainder 5 in case.

Answers

Answered by shiva0064
1

Answer:

Subtract remainder from each number

40-5=35

50-5=45

60-5=55

Take LCM of new no.s is4165 .this is your answer.please mark as brainlest answer

Answered by rajaman32
0

Step-by-step explanation:

first find lcm of these no.

40=2*2*2*5

50=2*5*5

60=2*2*3*5

lcm=600

the required no. which when divided leaves 5 remainder in each case will be

600+5

=605

Similar questions