Question

find the least number which when divided by 40 50 and 60 leaves remainder 5 in each case​

Answer 1

Answer:

605

Explanation:

LCM of 40, 50 and 60 = 600

600 + 5 = 605

Hence, 605 is the least number which when divided by 40, 50 and 60 leaves remainder 5 in each case.

Answer 2

Concept:

The required least number will be the LCM of the numbers 40, 50 and 60 added to the given remainder.

Given:

The given numbers are 40, 50 and 60.

The remainder is 5 in each case.

Solution:

First, we will find the LCM of the given numbers 40, 50 and 60 by prime factorization method.

$40=2\times2\times2\times5$

$50=2\times5\times5$

$60=2\times2\times3\times5$

The LCM of $40, 50$ and $60=2\times2\times2\times3\times5\times5$

                                          $=600$

The required least number$=600+5$

                                            $=605$

Hence, the required least number is 605 which when divided by 40, 50, and 60 leaves the remainder of 5 in each case.

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