Find the least number which when divided by 40, 50 and 60 leaves remainder 5 in each case.
Answers
Answered by
1
Answer:605
Step-by-step explanation:
1st. We should find the Least common multiple of 40, 50, and 60.
2nd. In this case that is 600. We add 5 and since all are larger numbers than 5 they will divide and always get a quotient of 15(40),12(50), 10(60) and a remainder of 5.
Answered by
2
Answer:
Answer is 605
Step-by-step explanation:
The required number is
LCM of ( 40,50,60 ) + 5
so LCM of 40,50,60 is
10×4×5×3 = 600 +5 =605.
so required least number is 605.
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