Question

Find the least number which when divided by 40, 50 and 60 leaves
remainder 5 in each case.​

Answer 1

Answer:

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Step-by-step explanation:

If the required number is N , then N−7 leaves a remainder of 0 when divided by 25, 40 and 60. Any multiple of their lowest common multiple will leave a remainder of 0. Their LCM is 600. Therefore N=600k+7 where k is an integer.

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Answer 2

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