Find the least number which when divided by 40, 50 and 60 leaves
remainder 5 in each case.
Answers
Answered by
2
Answer:
605
Step-by-step explanation:
Smallest common multiple of 40, 50 and 60 = L.C.M of 40, 50, 60
= 600
Since, we have to find the number when divided by 40,50,60 leaves the remainder 5 we have add 5 to 600.
600+5 = 605
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