Math, asked by banitadash41, 1 month ago

Find the least number which when divided by 40, 50 and 60 leaves
remainder 5 in each case.

Answers

Answered by RISHANK2006
2

Answer:

605

Step-by-step explanation:

Smallest common multiple of 40, 50 and 60 = L.C.M of 40, 50, 60

= 600

Since, we have to find the number when divided by 40,50,60 leaves the remainder 5 we have add 5 to 600.

600+5 = 605

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