Question

Find the least number which when divided by 40, 50 and 60 leaves remainder 5 in each case​

Answer 1

40-5 = 35

50-5 = 45

60-5 = 55

Now HCF od 35,45 and 55 is

35 = 5*7

45 = 3*3*5

55 = 5*11

HCF(35,45,55) = 5

Therefore,

The least number which when divided by 40, 50 and 60 leaves remainder 5 in each case​ is 5.

MARK IT AS THE BRAINLIEST PLZZZZZZZ.

Answer 2

Answer:

please show by factorisation method