Question

find the least number which when divided by 45, 60, leaves remainder 5 in each case

Answer 1

Hiiii. ...friend

The answer is here,

To find the least number , we have to find LCM for the numbers (45 & 60).

$= > \: 45 = {3}^{2} \times 5$

$= > \: 60 = {2}^{2} \times 5 \times 3$

$= > lcm \: = \: 5 \times {3}^{2} \times {2}^{2}$

LCM =180.


But it is given that , When this number is divided by 45 & 60 leaves the remainder 5.

So, The number => 180+5.

=> 185.

:-(Hope it helps u.