Math, asked by sukhmeet4340, 8 months ago

Find the least number which when divided by 48 ,64,72 and 80 leaves the remainders 38,54,62 and 70 Respectively

Answers

Answered by nmchopra
0

Answer:

2870

Step-by-step explanation:

Let us see the relation between the pairs of numbers, if there is any:

48-38=10

64-54=10

72-62=10

80-70=10

The difference is 10, so there is a pattern

LCM of 48 ,64, 72 and 80 = 2880 (see attachment for LCM)

Now, we will deduct 10 from 2880 to get 2870

CHECK

2870 ÷ 48 => 59Q + 38R

2870 ÷ 64 => 44Q + 54R

2870 ÷ 72 => 39Q + 62R

2870 ÷ 80=> 35Q + 70R

Attachments:
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