Question

find the least number which when divided by 5, 6, 7 &
8 leaves a remainder 3, but when divided by a 9
leaves no remainder.​

Answer 1

Answer:

your answer is 1683

Step-by-step explanation:

explanation has been provided above

hope this helps

Answer 2

Answer:

1683

Step-by-step explanation:

L.C.M. of 5, 6, 7 and 8 = 840

Required number =840x + 3

When the minimum value of x(840x + 3) is divided by 9

=> x = 2

Required number (840 x2 + 3) = 1683