Question

Find the least number which when divided by 5, 6 and 14 leaves 4 as the remainder.​

Answer 1

Answer:

The least number which when divided by 4, 5 and 6 leaves remainder 1, 2 and 3 respectively, is :

[A]57

[B]59

[C]61

[D]63

57

Here 4 – 1 = 3, 5 – 2 = 3, 6 – 3 = 3

∴ The required Number = LCM of (4, 5, 6) – 3

= 60 – 3 = 57.

Hence option [A] is correct answer.

Step-by-step explanation:

tum us question ko iski tarah Kar lo

Answer 2

Answer:

The least number which when divided by 5, 6, and 14 leaves 4 as the remainder is 214.

Step-by-step explanation:

Given:

Numbers 5,6 and 14

To Find:

The least number which when divided by 5, 6, and 14 leaves 4 as the remainder.​

Chapter/Concept:

LCM

Solution:
The least number that comes in the division with all the numbers given i.e. 5, 6, and 14. Will be calculated using LCM.

• 5 = 5 x 1
• 6 = 3 x 2 x 1
• 14 = 2 x 7 x 1

Lowest common multiple = 1 x 5 x 3 x 2 x 7

LCM = 210

210 is perfectly divided by all the numbers given to us

Adding 4 to the lowest common multiple

New number = 210 + 4 = 214

Conclusion:

The least number which when divided by 5, 6, and 14 leaves 4 as the remainder is 214

Verification:

Division by 5

214 is divisible by 5 x 42 will leave the remainder 4

Division by 6

214 is divisible by 6 x 35 will leave the remainder 4

Division by 14

214 is divisible by 14 x 5 will leave the remainder 4

Hence Verified.

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