Find the least number which when divided by 5,7,9 and 12, leaves the same
remainder 3 in each case
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Answered by
4
Answer:
To answer this , first we have to find the lcm and then add 3 to it .
LCM of 5 , 9 , 7 , 12 = 2² × 3² × 5 × 7
= 32400
Now if we add 3 to it , 32403
It is divisible by all four numbers leaving a remainder 3
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Answered by
0
Least number is 32403
Explanation:
Find the lcm and then add 3 to it .
LCM of 5 , 9 , 7 , 12 = 2² × 3² × 5 × 7
= 32400
Now if we add 3 to it , 32403
It is divisible by all four numbers leaving a remainder 3
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