Find the least number which when divided by 54, 63 and 81 leaves 6 as
remainder in each case.please solve step by step
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7
Answer:
1140
Step-by-step explanation:
Given
Find the least number which when divided by 54, 63 and 81 leaves 6 as remainder in each case
We need to find the LCM of the given numbers in order to find the least number. So
LCM of 54, 63 and 81 will be
Factors are 3 x 3 x 3 x 2 x 7 x 3 = 1134 + 6 = 1140
Now when we divide 1140 / 54 remainder is 6
1140 / 63 remainder is 6
1140 / 81 remainder is 6
So the least number will be 1140
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