Math, asked by akshat9030, 11 months ago

Find the least number which when divided by 54, 63 and 81 leaves 6 as
remainder in each case.please solve step by step​

Answers

Answered by knjroopa
7

Answer:

1140

Step-by-step explanation:

Given  

Find the least number which when divided by 54, 63 and 81 leaves 6 as remainder in each case

We need to find the LCM of the given numbers in order to find the least number. So  

LCM of 54, 63 and 81 will be

Factors are 3 x 3 x 3 x 2 x 7 x 3 = 1134 + 6 = 1140

Now when we divide 1140 / 54 remainder is 6

1140 / 63 remainder is 6

1140 / 81 remainder is 6

So the least number will be 1140

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