Find the least number which when divided by 54, 63, and 81 leaves 6 as remainder in each case
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Answer:
1140
Step-by-step explanation:
54= 2*3*3*3
63= 3*3*7
81= 3*3*3*3
L.C.M (54,63,81) = 2 * 3⁴ * 7
L.C.M. (54,63,81) = 1134
1134+6 = 1140
therefore, 1140 is the least number which when divided by 54, 63, and 81 leaves a remainder 6 in each case.
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