Find the least number which when divided by 6, 15, 18 leave remainder 5 in each case
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Answered by
54
LCM of 6, 15 and 18 = 90
When we divide 90 by 6, 15 and 18, it should leave remainder 5 in each case.
So, we add 5 to 90 = 95
95/6 quotient = 15, remainder = 5
95/15 quotient = 6, remainder = 5
95/18 quotient = 5, remainder = 5
∴ The answer is 95.
When we divide 90 by 6, 15 and 18, it should leave remainder 5 in each case.
So, we add 5 to 90 = 95
95/6 quotient = 15, remainder = 5
95/15 quotient = 6, remainder = 5
95/18 quotient = 5, remainder = 5
∴ The answer is 95.
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Answered by
19
LCM of 6,15 and18 is 90
then, when we divide 90 by all the three numbers i.e by 6, 15 and 18, the remainder should be 5.
therefore, adding 5 to 90=95
then, divide
95/6= 15, remainder=5
95/15=6, remainder=5
95/18=5, remainder=5
then, when we divide 90 by all the three numbers i.e by 6, 15 and 18, the remainder should be 5.
therefore, adding 5 to 90=95
then, divide
95/6= 15, remainder=5
95/15=6, remainder=5
95/18=5, remainder=5
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