Find the least number which when divided by 6 15 and 18 leave remainder 5 in each case
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Answer:
Step-by-step explanation:
LCM of
6 = 2x3
15 = 3x5
18 = 2x3x3
LCM = 2x3x3x5 = 90
5+90 = 95
The answer is 95.
When 95 is divided by 6, 15 or 18, the remainder is 5 in each case.
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