Question

Find the least number which when divided by 6, 15 and 18 leave remainder 5 in each case
(I need immediately plz)

Answer 1

Answer:

To solve this type of question firstly we will find the LCM of 6, 15 and 18 by the method of prime factorization shown in attachment.

When we find the the LCM of then LCM comes equal to 90.

after that after dividing by 6, 15 and 18 the number leaves remainder equals to 5,So

to live the remainder equals to 5 we should add 5 to their LCM.

So the number which came as final answer will be 90 + 5 = 95

Answer 2

$\huge{\textbf{Solution is attached here.}}$

The LCM of 6, 15, 18 is 90.

So, it proves that the least number which when divided by 6, 15 and 18 leave remainder 5 is = 90 + 5 = 95

I think 95 is the correct answer because the question says that we have to find the least number which when divided by these three numbers 6, 15 and 18. So that we have find the LCM to get that number. Then according to the question is that the number should leave remainder 5. So, we add 90 + 5 = 95.