Find the least number which when divided by 6, 15 and 18 leave remainder 7 in each case.
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Answer:
To find the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case, we have to find the L.C.M. of 6, 15 and 18 and then add 5 in that number. Hence, 95 is the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case.
Answered by
1
Answer:
Mate I think that your question is wrong, it should be-
FIND THE LEASE NUMBER WHICH WHEN DIVIDED BY 6,15 AND 18 LEAVES REMAINDER *5* IN EACH CASE
if this is the question, then you need to take the LCM of 6, 15 and 18 and then add 5 to it, which is
LCM of 6, 15 and 18 is 90
90+5=95
Haence, 95 is the answer
Step-by-step explanation:
Please mark it as brainlist
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