Find the least number which when divided by 6, 15, and 18 leave remainder 5 in code Case ?
Answers
Answered by
1
Answer:
95
Step-by-step explanation:
To find the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case, we have to find the L.C.M. of 6, 15 and 18 and then add 5 in that number. Hence, 95 is the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case.
Hope this answer will help you...
Answered by
1
Answer:
12 18 20 5 10 34 24 36 42 15 35 45
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