Math, asked by neitushukla, 6 months ago

Find the least number which when divided by 6, 15 and 18 leave remainder 5 in each case.

Answers

Answered by agrawalajay39

Answer:

Step-by-step explanation:

To find the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case, we have to find the L.C.M. of 6, 15 and 18 and then add 5 in that number. Hence, 95 is the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case.

L.C.M of 6, 15 and 18 = 2 x 3 x 3 x 5 = 90

Therefore the required number = 90+5=95

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