find the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case
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Answered by
1
Find the LCM of 6 , 15 & 18
6 = 2 × 3
15 = 5 × 3
18 = 2 × 3 × 3
LCM = 2 × 3 × 3 × 5
= 90
Now add 5
so your required number is 95
6 = 2 × 3
15 = 5 × 3
18 = 2 × 3 × 3
LCM = 2 × 3 × 3 × 5
= 90
Now add 5
so your required number is 95
Answered by
0
Hello..
L.C.M. of 6, 5 and 18
6 = 2*3
15 = 3*5
18 = 2*3*3
L.C.M. of 6, 15 and 18 = 2*3*3*5 = 90
Now,
5 + 90 = 95
Hence, 95 is the least number which is divided by 6, 15 and 18 leaves a remainder 5
Let us check our answer.
= 95/6
Quotient = 15
Remainder = 5
= 95/15
Quotient = 6
Remainder = 5
= 95/18
Quotient = 5
Remainder = 5
So, the required number is 95.
L.C.M. of 6, 5 and 18
6 = 2*3
15 = 3*5
18 = 2*3*3
L.C.M. of 6, 15 and 18 = 2*3*3*5 = 90
Now,
5 + 90 = 95
Hence, 95 is the least number which is divided by 6, 15 and 18 leaves a remainder 5
Let us check our answer.
= 95/6
Quotient = 15
Remainder = 5
= 95/15
Quotient = 6
Remainder = 5
= 95/18
Quotient = 5
Remainder = 5
So, the required number is 95.
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