Math, asked by aksharabinu001, 1 year ago

find the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case

Answers

Answered by Thatsomeone
1
Find the LCM of 6 , 15 & 18

6 = 2 × 3

15 = 5 × 3

18 = 2 × 3 × 3

LCM = 2 × 3 × 3 × 5

= 90

Now add 5

so your required number is 95
Answered by anshika1020
0
Hello..

L.C.M. of 6, 5 and 18 

6 = 2*3
15 = 3*5
18 = 2*3*3

L.C.M. of 6, 15 and 18 = 2*3*3*5 = 90

Now, 
5 + 90 = 95

Hence, 95 is the least number which is divided by 6, 15 and 18 leaves a remainder 5

Let us check our answer.

= 95/6
Quotient = 15
Remainder = 5

= 95/15
Quotient = 6
Remainder = 5

= 95/18
Quotient = 5
Remainder = 5

So, the required number is 95.
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