Question

Find the least number which when divided by 6, 15 and 18 leave remainders in each case​

Answer 1

Step-by-step explanation:

answer is 9 hope my answer is right

Answer 2

$first \: find \: the \: lcm \: of \\ 16 \: \: 15 \: \: 18 \\ = 2 \times 3 \times 3 \times 5 \\ = 90 \\ therefore \: the \: required \: number \\ = 90 \ + 50 \\ =95 \: answer$